Calculator and formulas for calculating a truncated cuboctahedron
This function calculates various properties of a truncated cuboctahedron. A truncated cuboctahedron has 12 square faces, 8 regular hexagonal faces, 6 regular octagonal faces, 48 vertices, and 72 edges.
To perform the calculation, select the property you know and enter its value. Then click on the 'Calculate' button.
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Volume
\(\displaystyle V= 2· a^3 · (11+7·\sqrt{2})\)
\(\displaystyle a= \sqrt[3]{ \frac{V}{2 ·(11+7· \sqrt{2})}} \)
Surface area
\(\displaystyle S= 12 · a^2 ·(2+\sqrt{2}+\sqrt{3})\)
\(\displaystyle a= \sqrt{ \frac{S}{12·(2+\sqrt{2}+\sqrt{3})}} \)
Outer radius
\(\displaystyle rc=\frac{a·\sqrt{13+6·\sqrt{2}}}{2} \)
\(\displaystyle a=\frac{2·rc}{ \sqrt{13+6·\sqrt{2}}} \)
Midsphere radius
\(\displaystyle rm=\frac{a·\sqrt{12+6·\sqrt{2}}}{2}\)
\(\displaystyle a= \frac{2 ·rm}{\sqrt{12+6·\sqrt{2}}} \)
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